Chapter 4 Forces and Mass Classical Mechanics Newton’s First Law
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Chapter 4 Forces and Mass Classical Mechanics Newton’s First Law
Chapter 4 Forces and Mass Newton’s First Law • • If the net force !F exerted on an object is zero the object continues in its original state of motion. That is, if !F = 0, an object at rest remains at rest and an object moving with some velocity continues with the same velocity. Classical Mechanics does not apply for • very tiny objects (< atomic sizes) • objects moving near the speed of light Forces • Usually a push or pull • Vector • Either contact or field force Contrast with Aristotle! Contact and Field Forces Fundamental (Field) Forces Types • Strong nuclear force • Electromagnetic force • Weak nuclear force • Gravity Electromagnetic Forces Strong Nuclear Force • • QCD (Quantum chromodynamics) confines quarks by exchaning gluons Nuclear force: binds protons and neutrons by exchanging pions • Opposites attract, like-signs repel • Electric forces bind electrons in atoms • Magnetic forces arise from moving charges Weak Nuclear Force Gravity • Involves exchange of heavy W or Z particle • Attractive force between any two bodies • Responsible for decay of neutrons • Proportional to both masses • Inversely proportional to square of distance F=G Inertia (Newton’s First Law) • Tendency of an object to continue in its original motion m 1 m2 r2 Mass • A measure of the resistance of an object to changes in its motion due to a force • Scalar • SI units are kg Newton’s Second Law • Units of Force Acceleration is proportional to net force and inversely proportional to mass. • ! ! ! F = ma SI unit is Newton (N) F = ma 1 N =1 • US Customary unit is pound (lb) • Weight kg ! m s2 1 N = 0.225 lb Weight vs. Mass Weight is magnitude of gravitational force mass w = mg weight M earth m r2 GM earth g= 2 Rearth w=G Newton’s Third Law ! ! F12 = ! F21 Single isolated force cannot exist • For every action there is an equal and opposite reaction Mass is inherent property • Weight depends on location Newton’s Third Law cont. • Force on “1” due to “2” • • • F12 is action force F21 is reaction force • You can switch action <-> reaction Action & reaction forces act on different objects Action-Reaction Pairs Define the OBJECT (free body) • ! ! n = ! n" Fg = !Fg' Newton’s Law uses the forces acting ON object • n and Fg act on object • n’ and Fg’ act on other objects Assumptions for F=ma Definition of Equilibrium ! !F = 0 • Objects behave as particles • • ignore rotational motion (for now) Consider only forces acting ON object • neglect reaction forces Example 4.1a Example 4.1b A Ford Pinto is parked in a parking lot A Ford Pinto is parked in a parking lot There is no net force on the Pinto A) True B) False The contact force acting on the Pinto from the parking lot surface ______________ . A) Points upwards B) Is zero C) Points downward Example 4.1c Example 4.1d A Ford Pinto drives down a highway on the moon at constant velocity (where there is no air resistance) A Ford Pinto drives down a highway on the moon at constant velocity (where there is no air resistance) The Pinto’s acceleration is __________ The force acting on the Pinto from the contact with the highway is vertical. A) Less than zero B) Equal to zero C) Greater than zero Mechanical Forces A) True B) False Some Rules for Ropes and Pulleys • Strings, ropes and Pulleys • Force from rope points AWAY from object • Gravity • Normal forces Magnitude of the force is tension • • • Friction Tension does not change when going over frictionless pulley • Springs (later) Example 4.2 a) Find acceleration b) Find T, the tension above the bowling ball c) Find T3, the tension in the rope between the pails d) Find force ceiling must exert on pulley a) a = g/6 = 1.635 m/s2 b) T = 57.2 N Example 4.3a 2) Which statements are correct? Assume the objects are static. T1 is _____ T2 A) Less than B) Equal to C) Greater than c) T3=24.5 N d) Fpulley=2T = 114.5 N cos(10o)=0.985 sin(10o)=0.173 Example 4.3b Example 4.3c 2) Which statements are correct? Assume the objects are static. 2) Which statements are correct? Assume the objects are static. T2 is ______ T3 T1 is _____ Mg A) Less than B) Equal to C) Greater than A) Less than B) Equal to C) Greater than cos(10o)=0.985 sin(10o)=0.173 cos(10o)=0.985 sin(10o)=0.173 Example 4.3d Example 4.4 2) Which statements are correct? Assume the objects are static. T1+T2 is ______ Mg A) Less than B) Equal to C) Greater than cos(10 )=0.985 sin(10o)=0.173 o Given that Mlight = 25 kg, find all three tensions T3 = 245.3 N, T1 = 147.4 N, T2 = 195.7 N Cable Pull Demo Inclined Planes • Choose x along the incline and y perpendicular to incline • Replace force of gravity with its components Fg,x = mgsin ! Fg,y = mg cos! Example 4.5 Example 4.6 (Skip) M Find the acceleration and the tension Find M such that the box slides at constant v a = 4.43 m/s2, T= 53.7 N M=15.6 kg Forces of Friction Sliding Friction • RESISTIVE force between object and neighbors or the medium • Examples: • Sliding a box • Air resistance • Rolling resistance Coefficients of Friction f ! µs N f = µk N µs > µk • Parallel to surface, opposite to other forces • ~ independent of the area of contact • Depends on the surfaces in contact Static Friction, ƒs fs ! µ s N f ! µs N f = µk N µs > µk • µs is coefficient of static friction • f N is the normal force F Friction Demo Kinetic Friction, ƒk f = µk n • f µk is coefficient of kinetic friction • Friction force opposes F • n is the normal force F Example 4.7 Example 4.8 The man pushes/pulls with a force of 200 N. The child and sled combo has a mass of 30 kg and the coefficient of kinetic friction is 0.15. For each case: What is the frictional force opposing his efforts? What is the acceleration of the child? f=59 N, a=3.80 m/s2 / f=29.1 N, a=4.8 m/s2 Example 4.9 Given m1 = 10 kg and m2 = 5 kg: a) What value of µs would stop the block from sliding? b) If the box is sliding and µk = 0.2, what is the acceleration? c) What is the tension of the rope? a) µs = 0.5 b) a=1.96 m/s2 Other kinds of friction • Air resistance, F ~ Area " v2 • Rolling resistance, F ~ v Terminal velocity: What is the minimum µs required to prevent a sled from slipping down a hill of slope 30 degrees? µs = 0.577 Fresistance = CAv 2 = mg at terminal velocity c) 39.25 N Coffee Filter Demo Example 4.9 An elevator falls with acceleration a = 8.0 m/s2. If a 100-kg person stood on a bathroom scale during the fall, what would the scale read? 18.45 kg Accelerating Reference Frames • Fictitious Force: Derivation Equivalent to “Fictitious” gravitational force g fictitious = !a frame 1 x = v0 t + at 2 2 1F 2 = v0 t + t 2m Eq. of motion in fixed frame 1 af t2 2 1 (F ! ma f ) 2 x ! x0 (t) = v0 t + t 2 m x0 (t) = F-maf looks like force in new frame, maf acts like fake gravitational force! Example 4.11a Example 4.10 You are calibrating an accelerometer so that you can measure the steady horizontal acceleration of a car by measuring the angle a ball swings backwards. If M = 2.5 kg and the acceleration, a = 3.0 m/s2: a) At what angle does the ball swing backwards? b) What is the tension in the string? A fisherman catches a 20 lb trout (mass=9.072 kg), and takes the trout in an elevator to the 78th floor to impress his girl friend, who is the CEO of a large accounting firm. The fish is hanging on a scale, which reads 20 lb.s while the fisherman is stationary. Later, he returns via the elevator to the ground floor with the fish still hanging from the scale. # # = 17 deg T= 25.6 N In the instant just after the elevator begins to move upward, the reading on the scale will be ______________ 20 lbs. a) Greater than b) Less than c) Equal to Example 4.11b A fisherman catches a 20 lb trout (mass=9.072 kg), and Example 4.11c A fisherman catches a 20 lb trout (mass=9.072 kg), takes the trout in an elevator to the 78th floor to impress and takes the trout in an elevator to the 78th floor his girl friend, who is the CEO of a large accounting firm. to impress his girl friend, who is the CEO of a large The fish is hanging on a scale, which reads 20 lb.s while accounting firm. The fish is hanging on a scale, which the fisherman is stationary. Later, he returns via the reads 20 lb.s while the fisherman is stationary. Later, elevator to the ground floor with the fish still hanging he returns via the elevator to the ground floor with from the scale. the fish still hanging from the scale. On the way back down, while descending at In the instant just before the elevator comes to constant velocity, the reading on the scale will be ________________ 20 lbs. a) Greater than b) Less than c) Equal to a stop on the 78th floor, the mass of the fish a) Greater than will be ______________ 9.072 kg. b) Less than c) Equal to