...

Sound insulation

by user

on
Category: Documents
29

views

Report

Comments

Transcript

Sound insulation
Sound insulation
23 November 2012
Sound insulation
1
Sound against a wall
• Balance of sound energy
impinging over a wall
• The energy balance shows
three main fluxes:
– Reflected
– Absorbed
– Transmitted
• Hence three coefficients are
defined, as the ratios with the
impinging energy
23 November 2012
16
Sound
SoundAbsorption
insulation
r+a+t =1
2
Materials: sound insulating & sound absorbing
Sound absorbing materials must not be confused with sound insulating
materials:
Sound Insulating material:
Heavy and stiff, minimizes
transmitted power “Wt”.
the
Sound Absorbing material:
Soft and porous, minimizes
reflected power “Wr”.
23 November 2012
16
the
Sound
SoundAbsorption
insulation
3
The Sound Reduction Index R
With regard to a sound imping over a wall we define t as:
• transmission coefficient:
Wt
t
Wo
It is the ratio between the transmitted power Wt and the incident
power Wo.
The Sound Reduction Index R of a wall characterized by a
transmission coefficient t is given by:
• Sound Reduction Index:
(dB)
23 November 2012
Sound insulation
1 
R  10 log 10  
t 
4
Change of R with frequency
4 different frequency ranges can be identified:
• Rigidity region,
6 dB/octave.
R
drops
by
• Resonance region (the whole panel
is affected by resonances and
antiresonances).
• Mass region,
6 dB/octave.
R
increses
by
• Coincidence region (coincidence between wavelength in air and inside the
flexural vibrations of the panel make the Sound Reduction Index to drop).
23 November 2012
Sound insulation
5
The mass law
R = 20 × lg (s × f ) - 42.5
(theoretical)
R = 20 × lg (s × f ) - 44.0
(practical)
• The value of R increses by 6 dB when doubling the frequency.
• The value of R increases by 6 dB when doubling the mass of the wall
Single Wall
Double Wall
Two separate walls
R = 30 dB
R = 36 dB
R = 60 dB
23 November 2012
Sound insulation
6
Coincidence frequency
• Example: steel, Fcr=97700 Hzm2/kg,  = 8.1 kg/(m2mm)
• s = 10mm, hence  = s = 8.110 = 81 kg/m2
• fcoinc = Fcr/ = 97700/81 = 1206 Hz
23 November 2012
Sound insulation
7
Sound Insulation D vs Sound Reduction Index R
•
•
The Sound Reduction Index R is defined by:
1
R = 10× log
t
The Sound Insulation D is defined by:
D = L1 - L2
•
We can make an energy balance of the energy
passing through the separating wall, having
surface Sdiv, and reverberating in room 2,
having an equivalent absorption area A2:
I1 × S × t = I 2 × A2
•
After some math passages, we get the
relationship between R and D:
23 November 2012
Sound insulation
Sdiv
R = L1 - L2 +10 × log
A2
Sdiv
R = D +10 × log
A2
8
Apparent Sound Reduction Index R’
• Theory – definition of t and R
• Practice – lab measurement (R)
no flanking transmission
R ³ R'
( R - R') @ 3¸ 5
dB
• Practice – in situ measurement (R’)
significant flanking transmission
23 November 2012
Sound insulation
9
Weighted Sound Reduction Index RW
• A reference curve is shifted down at 1 dB steps, until the sum of
unfavourable deviations becomes smaller than 32 dB
• At this point, the weighted value of the Sound Insulation Index, Rw,
is read on the reference curve at the frequency of 500 Hz.
23 November 2012
Sound insulation
10
Fly UP